Chemistry, asked by afifasameenshaik, 9 months ago

CH2=CHCH2Br+H2O GIVES

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Answered by anjalikawarkhe30

Explanation:

The given compound is allyl bromide.

3-Bromoprop-1-ene is the IUPAC name.

In CH2=CH-CH2-Br ,

Double bond gets the priority. -Br here is a substituent. So, numbering is done from left to right so that carbon containing double bond gets least number (lowest locant number).

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CH2=CHCH2Br+H2O GIVES​

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CH2=CHCH2Br+H2O GIVES