Question

ch2p2.9q47

Plz explain in detail step by step. ​

Answer 1

$heya \\ \\ \\ \\ log_{10}(5) - log_{10}(8) + log_{10}(16) = x \\ \\ \\ \\ log_{10}(5 \div 8) + log_{10}(16) = x \\ \\ \\ \\ log_{10}(5 \times 16 \div 8) = x \\ \\ \\ \\ log_{10}(10) = x \\ \\ \\ x = 1 \\ \\ \\ \\ formula \: \: used \: \: \: \\ \\ \\ log(m) - log(n) = log(m \div n) \\ \\ \\ \\ log(m \times n) = log(m) + log(n)$