Question

ch2pg2.8q38,39

plz explain in detail step by step both the Q.s​

Answer 1

$heya \\ \\ \\ \\ log(2x - 3y) = log(x \div y) \\ \\ becoz \: \: log(x) - log(y) = log(x \div y) \\ \\ \\ \\ = > \\ \\ 2x - 3y = x \div y \\ \\ \\ 2xy - 3y {}^{2} = x \\ \\ x = 3y {}^{2} \div (2y - 1) \\ \\ \\ \\ 2) \\ \\ \\ xyz = log_{24}(12) \times log_{36}(24) \times log_{48}(36) \\ \\ \\ xyz+1 =$2