(CH3)C-O-CH3 on reaction with HI give CH3OH and (CH3)3C-I as main product and not (CH3)C-OH and CH3I. give reason
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because (CH3)3C+ there is formation of 3° stable carbocation and I- act as nucleophile and there is formation of CH3O- on which H+ attacks and CH3OH forms.
I hope it will help u..
I hope it will help u..
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Hey dear,
● Explanation -
- Tert.butyl methyl ether on reaction to form carbocation.
- As 3° carbonations are more stable than 1° ones, it's much easier for H+ to attack O-CH3 bond than O-C(CH3)3 bond to form CH3OH.
- Hence, ter.butyl methyl ether on reaction with HI gives CH3OH and (CH3)3C-I.
(CH3)3C-O-CH3 + HI --> (CH3)3C-I + CH3OH
Hope this helps you...
● Explanation -
- Tert.butyl methyl ether on reaction to form carbocation.
- As 3° carbonations are more stable than 1° ones, it's much easier for H+ to attack O-CH3 bond than O-C(CH3)3 bond to form CH3OH.
- Hence, ter.butyl methyl ether on reaction with HI gives CH3OH and (CH3)3C-I.
(CH3)3C-O-CH3 + HI --> (CH3)3C-I + CH3OH
Hope this helps you...
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