Question

CH3 CH = CH 2---H2O--->
NaoH,
HLB H2) 2 excus
H2o H2O2, OH-​

Answer 1

Explanation:

Hydroboration-oxidation reaction follows anti-Markovnikov's addition of H−OH across C=C to give alcohol.

Thus an alkene CH

3

CH=CH

2

when treated with B

2

H

6

in presence of H

2

O

2

will yield the final product as CH

3

CH

2

CH

2

OH