Question

CH₃ - CH = CH₂ □(→┴(i) Hg(OAc)₂/H₂O)X + Na
→ Y + CH₃Cl → Z + HI □(→┴0°C) A + B
What are A and B ?
(a) CH₃ – CH₂ – CH₂ – OH & CH₃I
(b) CH₃ – CH – OH & CH₃I
|
CH₃
(c) CH₃ – CH – I & CH₃OH
|
CH₃
(d) CH₃ – CH₂CH₂I & CH₃OH

Answer 1

Answer:

You may take help of Google or YouTube

Answer 2

A and B are :

Reaction : CH₃ - CH = CH₂ □(→┴(i) Hg(OAc)₂/H₂O) X + Na → Y + CH₃Cl → Z + HI □(→┴0°C) A + B

1. CH₃ - CH = CH₂ (→┴(i) Hg(OAc)₂/H₂O) X

When propene reacts with Hg(OAc)₂/H₂O, it follows ' Oxymercuration-Demercuration of Alkenes '.

In that reaction, alkenes are converted into alcohols following the Markovnikov's rule.

X = CH₃ - CH(OH) - CH₃

2. CH₃ - CH(OH) - CH₃ + Na → CH₃ - CH(ONa) - CH₃

3. CH₃-CH(ONa)-CH₃ + CH₃Cl → CH₃-CH(OCH₃)-CH₃ + NaCl

4. CH₃-CH(OCH₃)-CH₃ +HI → CH₃-CH(OH)-CH₃ + CH₃I

A = CH₃ – CH – OH & B = CH₃I

|

CH₃

Correct option : (b)