Question

) CH3-CH2-CH2-O-CH3+HBr →
i) CH-CH=CH HẠO H ,
i) CHACHACH-CHO NaBH.
TY​

Answer 1

Answer:

CH3-CH2-CH2-O-CH3+HBr →CHACHACH-CHO NaBH

Answer 2

ANSWER

CH

3

O−CH=CH

2

+H

+

Br

−

→CH

3

O−CHBr−CH

3

HBr protonates the double bonded C of alkene which make a resonance-stabilized cation

CH

3

−CH

+

−OCH

3

⇌CH

3

CH=O

+

CH

3

. This can add Br

−

at the CH carbon.