CH3-CH2-CH2-OH. WRITE THE STRUCTURE OF THE ESTER FORMED WHEN THIS ALCOHOL REACT WITH AN ACID CH3 COOH
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When, Propanol(CH₃(CH₂)₂OH) reacts with Ethanoic acid(CH₃COOH)
C₃H₇OH+CH₃COOH→C₃H₇COOCH₃+H₂O
The formula of the ester compound formed is CH₃CH₂CH₂COOCH₃ (Propyl Ethanoate)
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