Question

ch3 ch2 cl react on base​

Answer 1

Explanation:

Chlorobenzene reacts with methyl chloride in presence of anhydrous aluminium chloride to give mixture of 1−chloro−4−methylbenzene (major) and 1−chloro−2−methylbenzene (minor)

(b) Ethyl chloride reacts with potassium cyanide to form ethyl cyanide.

CH

3

−CH

2

−Cl+KCN

Δ

CH

3

−CH

2

−CN+KCl

(c) A molecule of HI is added to double bond of propene to form 2−iodopropane . Addition follows Markownikoff's rule.

CH

3

−CH=CH

2

+HI→CH

3

−CH(I)−CH

3

(d) In presence of sulphuric acid, ethanol reacts with NaBr to form ethyl bromide.

CH

3

−CH

2

−OH+NaBr+

2

1

H

2

SO

4

→CH

3

−CH

2

−Br+H

2

O+

2

1

Na

2

SO

4