CH₃ CHO + CH3 ch2 MgBr
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Acetaldehyde reacts with methyl magnesium bromide followed by hydrolysis to give propan-2-ol (compound A). This on heating with sulphuric acid undergoes dehydration to form 1-propene (compound B).
Hydroboration oxidation gives propan-1-ol (compound C).
Thus, compounds A and C are positional isomers.
Hence, the correct option is B
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