Chemistry, asked by Anonymous, 8 months ago

(CH3)COCH3and CH3OC2H5 are treated with hydroiodic acid.the fragments obtained after reaction Are ​

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Answered by pari3376
1

Answer:

The fragments obtained after reaction of (CH3)3COCH3 and CH3OC2H5 with hydroiodic acid are (CH3)3CI + CH3OH; CH3I + C2H5OH. groups. Methyl iodide is formed when one group is methyl and the other a primary or secondary alkyl group.

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