Question

CH3-O-C-CH2-COOH
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plzz do let me know how to do naming of this compound as here carboxlyic acid will get priority and ester will act as a prefix so if we start numbering from cooh how this compound will be 2-methoxycarbonyl ethanoic acid plz do give an explanation
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Answer 1

Answer:

In the compound both ketone and the carboxylic group is present. Priority is given to carboxylic group at C-1, and the ketonic group at C-3 is treated as a substituent. Thus the prefix used is "keto" and the suffix used is "oic acid".

Thus IUPAC name is ketobutanoic acid