CH3ch2br +kcn in presence of ethanol product
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Answer:
CH3CH2Br+KCN=CH3CH2CN
Answered by
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The reaction is shown below.
CH₃CH₂Br + KCN → CH₃CH₂CN + KBr
Whenever alkyl bromides, in the form if R-X, where R is the alkyl group and X is the halogen group, react in presence of KCN (potassium cyanide), then alkyl cyanides R-CN are produced as the main product and potassium halide, K-X is produced as the by-product.
The reaction is shown below:
CH₃CH₂Br + KCN → CH₃CH₂CN + KBr
Ethyl cyanide (CH₃CH₂CN) is the main product.
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