Physics, asked by souvankarmakar26, 4 months ago

CH3CH2CH2BR+C2H5Oreaction with KOH

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Answered by Anonymous

A reaction called as Dehalogenation takes place when CH3CH2CH2Br or 1-Bromopropane (Alkyl halide/Haloalkane) is reacted with alcoholic KOH, this lead to the formation of 1-Propanol (an alcohol) and Potassium Bromide.

CH3CH2CH2Br + KOH(alcoholic)-------> CH3CH2CH2OH + KBr

Answered by aryashreechhetri

Answer:

It's full form isContinuous and Comprehensive Evaluation .

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CH3CH2CH2BR+C2H5Oreaction with KOH​

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CH3CH2CH2BR+C2H5Oreaction with KOH