Question

CH3CHBrCH2Br + alc KOH = ?​

Answer 1

$\huge{\textbf{\textsf{{☆ An}}{\purple{sw}}{\pink{er ☆} \: {{}{:}}}}}$

Haloalkanes in the presence of alcoholic KOH undergoes elimination reaction or dehydrohalogenation reaction.

CH3CH2CH2Br+alc.KOH→CH3CH=CH2+KBr+H2O