CH3CHBrCH2CH3 + Br2 inthe presance of sunlight?
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Answer:
This method follows free radical mechanism and forms alkyl halide.
Here, the reactivity of hydrogen is 3
o
>2
o
>1
o
. So,2-methylbutane on reaction with Br
2
in the presence of sunlight gives 2-bromo-2-methylbutane.
CH
3
CH
2
CH(CH
3
)CH
3
Br
2
CH
3
CH
2
C(CH
3
)BrCH
3
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