CH3CONH2 +Br2 /NAOH
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Hey mate...
When CH3CONH2 , acetamide reacts with KOH. Br2, we get methylamine, CH3NH2
The reaction is
CH3CONH2 −→−Br2KOH CH3NH2 + KBr
Here the reaction begins with the reaction with Br2, leading to formation of isocyanate which further hydrolysis to give the desired product.
Hope this helps u....
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