Question

CH₃OC₂H₅ and (CH₃)₃ C – OCH₃ are treated with hydriodic
acid. The fragments obtained after reactions are
(a) CH₃I + HOC₂H₅; (CH₃)₃ CI + HOCH₃
(b) CH₃OH + C₂H₅I; (CH₃)₃ Cl + HOCH₃
(c) CH₃OH + C₂H₅I; (CH₃)₃COH + CH₃I
(d) CH₃I + HOC₂H₅; CH₃I + (CH₃)₃ COH.

Answer 1

Explanation:

CH₃OC₂H₅ and (CH₃)₃ C – OCH₃ are treated with hydriodic

acid. The fragments obtained after reactions are

(a) CH₃I + HOC₂H₅; (CH₃)₃ CI + HOCH₃

(b) CH₃OH + C₂H₅I; (CH₃)₃ Cl + HOCH₃

(c) CH₃OH + C₂H₅I; (CH₃)₃COH + CH₃I

(d) CH₃I + HOC₂H₅; CH₃I + (CH₃)₃ COH.✔️

Answer 2

$\huge{\underline{\mathbb{\red{Answer}}}}$

(d) CH₃I + HOC₂H₅; CH₃I + (CH₃)₃ COH.

$\huge{\underline{\underline{\mathfrak{Thank you}}}}$