CH3OH is an alkali because is contain OH
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Explanation:
was asked to find the most basic solution from the following:
K2SO4
CH3OH
Na2CO3
(NH4)2CrO4
BaCl2
I know that I have to identify the solution that contains the conjugate base of a weak acid.
Knowing this, I immediately eliminated BaCl2 (HCl), K2SO4 (H2SO4), and (NH4)2CrO4 (H2CrO4 — which I've heard is a strong acid).
This left CH3OH and Na2CO3.
The correct answer is Na2CO3 since CO32− is the conjugate base of H2CO3.
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