Question

CH4
16
value of n.
54. Under the same conditions, a gas diffuses 2 times as fast
as SO2 gas. Find the molecular mass of the gas.
55. Besides the lower layer, CO, is also found in the upper​

Answer 1

Q54.

According to the question.

$dso2 \div 2dso2 = \sqrt{m2 \div m1}$

1/2 = √64 ÷√m1

16 =√m1

m1 = 4g/mol