Question

ch4+2o2-----co2+2h2
how many grams of CO2 is evolved in this reaction
2)what is the no of moles of methane required to react with 128 g of oxygen​

Answer 1

Explanation:

n = m/M, where;

n = moles

m = mass (g) = 128 g O2

M = molar mass (g/mol) = 2 × 15.999 g/mol O = 31.998 g/mol O2

n O2 = 128 g O2/31.998 g/mol = 4.00 mol O2

Calculate moles CH4 needed to react completely with 4.00 mol O2 (128 g O2).

Multiply 4.00 moles of O2 by the mole ratio between O2 and CH4 in the balanced equation, so that mol O2 cancel, leaving mol CH4.

4.00 mol O2 × 1 mol CH4/2 mol O2 = 2.00 mol.