CH4 + 2O2 = CO2 + 2H2O at STP.
Number of moles of CH4 and O2 used in combustion reaction of 22.4L of CH4 with 128 g of O2 is ____
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Answer:
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Explanation:
C
6
H
5
OH(g)+O
2
(g)⟶CO
2
(g)+H
2
O(l)
22.4L 22.4L
at NTP at NTP
∵ 22.4L C
6
H
5
OH reacts with 22.4L of O
2
∴ 30ml C
6
H
5
OH reacts with
22.4
22.4
×30=30ml
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