CH4 diffuses twice as fast as Y.mol. Wt. Of Y is??
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molecular mass of CH4 =16
Rate of diffusion is inversely proportional to the square root of molecular mass,
Rate of diffusion of CH4 be r
Rate of diffusion of Y be r2
Given: r=2r2
(2r÷r)×(2r÷r)=mol mass of Y ÷16
64=mol mass of Y
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