Question

CH4​ diffuses two times faster than a gas X. The number of molecules present in 32g of gas X is ____: (N is Avogadro's number.)

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Answer 1

Answer:

CH4 diffuses two times faster than a gas X . The number of molecules present in 32 g of gas X is :( N is Avogadro number)

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Using graham's law of diffusion, rCH4rgas = √(mgasmCH4) 2 = √(mgas16) mgas = 64 Number of molecules = wmolar mass × N = 3264 × N = N2 .Hence, the ... More

Answer 2

Answer:

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