Ch4, nh3, h2o have same hybridization but different geometry why
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CH4 doesn't have lone pair of electrons ,but NH3 and H2O have lone pair of electrons ,
these lone pair of electrons repel the bonding pair which changes its geometry then CHi
in water oxygen has two lone pairs while in NH3 nitrogen has one lone pair.
lone pair_lone pair repulsion is greater than lone pair - bond pair which is greater than bond pair -bond pair
so in water oxygen has two lone pairs so it has more repulsion and in NUt there is only one lone pair of electron on nitrogen so lone pair bond pair repulsion is less than that of lone pair -lone pair repulsion in water This is the reason due to which they have different geometry
_____hope it helps u____
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these lone pair of electrons repel the bonding pair which changes its geometry then CHi
in water oxygen has two lone pairs while in NH3 nitrogen has one lone pair.
lone pair_lone pair repulsion is greater than lone pair - bond pair which is greater than bond pair -bond pair
so in water oxygen has two lone pairs so it has more repulsion and in NUt there is only one lone pair of electron on nitrogen so lone pair bond pair repulsion is less than that of lone pair -lone pair repulsion in water This is the reason due to which they have different geometry
_____hope it helps u____
☺☺☺☺☺☺☺☺☺☺
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Answer because shapes of hybridization element depends upon lone pair electron then the ch4 has no lone pair, in nh3 they have only one lone pair and h2o has 2 lone pair so according to this shape is change
Explanation:
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