Question

ch4+o2 = co2 + h2o if 32 gram of ch4 is taken how much volume of o2 is needed and haw much mass of h2o will be produced​

Answer 1

Answer:

Vol of O2 - 44.8 L

Mass of H2O Produced = 36 gm

Explanation:

32g of CH4 - 2 MOLES OF CH4 (32/16)

1 mol CH4 required 1 mol O2

So 2 mol CH4 required 2 mol of O2

As we know volume of 1 mol O2 is 22.4 L

So volume of O2 required = 2*22.4 = 44.8 L

1 Mol CH4 = 1 MOL H2O

1MOL H2O = 18 G

2 MOL CH4 GIVES 2 MOL H2O

2 MOL H2O =18*2 = 36 gm