Question

CH4 takes 36 mins to effuse from container.How long will He gas take to diffuse from the same container under the same condition ...?

Answer 1

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Answer 2

Tch4= 36 min = 36/60 = 0.6 sec

Vch4 = 22.4 dm3 ( velocity is not given so we take constant velocity )

Mch4 = 16 a.m.u

T(he) = ?

Vhe = 22.4 dm3 ( conditions for container is same )

Mhe = 4 a.m.u

Formula:

√(Mhe/Mch4) = ( Vch4/tch4 )/( Vhe/the )

√(4/16) = (22.4/0.6)/ 22.4/the) ( both volumes will cut each other )

√0.25 = t(he)/0.6

0.5 = t(he)/0.6

T(he) = 0.5× 0.6

T(he) = 0.3 sec