Question

Chal be question 6 solve kar sorry for this language i mark you in brainlist

Answer 1

Answer:

0.12M AND 2.5Ω

Explanation:

R = RESISTANCE = 10Ω

(Rho) = RESISTIVITY = $1.6 X 10^{-6}$Ω$m^{-1}$

L = LENGTH

r = RADIUS = DIAMETER/2= $\frac{0.5X10^{-3}}{2} m = 0.25 X 10^{-3}m$

A = AREA = $\pi r^2= 3.14X (0.25X10^{-3})^2$

$R= \frac{(Rho)L}{A} => L = \frac{RXA}{(Rho)} = \frac{3.14X (0.25X10^{-3})^2 }{1.6X10^{-6}}\\=\frac{3.14X0.25X0.25}{1.6} =0.12m$

IF THE DIAMETER IS DOUBLED,THE RADIUS GETS DOUBLED ( r' = 2r ).

AND R IS PROPORTIONAL TO $r^{-2}$

R = K r ⁻²

R' = K (r') ⁻² = K (2r)⁻² = $\frac{Kr^{-2}}{4}=\frac{R}{4}$

R' =10/4 = 2.5Ω

IF THE DIAMETER IS DOUBLED,THE RESISTANCE DECREASES TO ONE FORTH OF ORIGINAL RESISTANCE.