Question

Challange..!! construct a quadrilateral PQRS in which PQ = 5 cm, QR = 6.5 cm, angle P = angle R = 100° and angle S = 75° . [ Hint angke Q = 360° -(100°+ 100° +75°) = 85°]

Answer 1

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Answer 2

Given :  a quadrilateral PQRS

PQ = 5cm , QR = 6.5cm , ∠P = ∠R = 100° and ∠S = 75°

To Find : construct  quadrilateral PQRS

Solution:

Sum of all the angles of a quadrilateral = 360°

∠P = ∠R = 100° and ∠S = 75°

∠P + ∠Q + ∠R  +  ∠S = 360°

=> ∠Q = 85°

Step 1 :  Draw a line segment PQ  = 5 cm

Step 2 : Draw an angle of 85° at Q on PQ using Protractor

Step 3 : Take a length of 6.5 cm from Q on angle drawn and label as R

Step 4 :  Draw an angle of 100° at R on QR using Protractor

Step 5 :  Draw an angle of 100° at P on PQ using Protractor intersecting angle drawn in pervious step at S

Quadrilateral PQRS is constructed

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