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Motion of a particle along a straight line is described by equation X= 8 + 12t - t^3
Where X is in metre and t is in second, What is retardation of particle when its velocity becomes zero?
Please give full solution...
JinKazama1:
Is retardation is 12m/s^2
dont know
It is correct :
Where did you get ? This q
yes it is correct..
my friend asked me...
Answers
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Heya!
X = 8 + 12t - t³
v = dx/dt = (0) + 12 - 3t²
When, v = 0
12 - 3t² = 0
12 = 3t²
t = 2 sec.
Now, a = dv/dt = -6t
So, retardation = 12 m/s²
X = 8 + 12t - t³
v = dx/dt = (0) + 12 - 3t²
When, v = 0
12 - 3t² = 0
12 = 3t²
t = 2 sec.
Now, a = dv/dt = -6t
So, retardation = 12 m/s²
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