Question

!!!! CHALLENGE !!!! 100 points
ABCD is a trapezium with AB parallel to DC . If AB=10 cm , AD=BC=4cm and angle DAB = ANGLE CBA =60



CALCULATE

1. THE LENGTH OF CD
2.THE DISTANCE BETWEEN AB AND CD




{ANSWER: 1.) 6CM
2.)
$2 \sqrt{3}$
}​

Answer 1

Answer:

Step-by-step explanation:

From  △ADP,

AP/AD=cos60∘

=> x4=12

=> x = 2

Therefore, CD = AB - 2x = 10 - 4 = 6 cm

Answer 2

From △ADP,

AP/AD=cos60∘

=> x4=12

=> x = 2

Therefore, CD = AB - 2x = 10 - 4 = 6 cm

3.7