Math, asked by deepakswim, 11 months ago

CHALLENGE!
Factorise:
e. 1.6x² - 4y²/
2y+0.4x​

Answers

Answered by anshul31463
0

1.6 {x}^{2}  - 4y { }^{2}  \div 2y + 0.4x

answer is =

1.6x {}^{2}  - 2y  + 0.4x

Answer is that

Answered by vidyapeethschoolms
0

0.4(4 {x}^{2}  - 10 {y}^{2} ) \0.4(5y + x) \\  ({2x})^{2}  -  (\sqrt{10}  {y})^{2)

0.4(4 {x}^{2}  - 10 {y}^{2} ) \div 0.4(5y + x) \\  = (2 {x})^{2}  -  (\sqrt{10}y) {}^{2}  \div 5y + x \\  = (2x +  \sqrt{10} y)(2x  - \sqrt{10} y) \div 5y + x

a

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