Question

##CHALLENGE FOR EVERYONE##

**LET'S SEE WHO CAN SOLVE THIS QUESTION**

Q. Prove thàt;
$\frac{1 - \tan \alpha }{1 + \tan\alpha } = { \cos}^{2} \alpha + { \sin}^{2} \alpha$
**NO USELESS ANS. PLEASE**

Answer 1

The ques should be 1-tanα / 1+tanα = cos²α - sin²α
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Taking LHS

= 1-tanα / 1+tanα

= 1/1-sinα/cosα / 1/1+sinα/cosα

= cosα-sinα/cosα / cosα+sinα/cosα

= cosα-sinα / cosα+sinα

= (cosα-sinα)(cosα+sinα) / (cosα+sinα)(cosα+sinα)

= (cos²α -sin²α) / (cos²α+sin²α)

= (cos²α-sin²α) / (1)²

(because sin²α+cos²α = 1)

= cos²α - sin²α   = RHS

Hence Proved
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Answer 2

Answer:

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