Question

Challenge for just fully qualified answerers not for others!

• A table top measures 2 m 25 cm by 1 m 50 cm. What is perimeter of the table. Give anser in both units one by one.

• A rectangular piece of land measure 0.7 km by 0.5 km Each side is to be fenced with r rows of wires. What is length of wire needed?

• The lid of rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of he tape required?

• Show that perimeter of rectangle is 2(l+b) units.

Note!

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• Questions are more that's why given more points than 5. answer properly.

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Answer 1

Answer:

• Length of table = 2m 25cm

Breadth of table = 1m 50cm

Perimeter of table = 2 ( l + b )

= 2 ( 225 + 150 )

= 2 × 375

= 750 cm

= 7m 50cm

• Length of rectangular land = 700m

Breadth of rectangular land = 500m

Perimeter of rectangular land = 2( l + b )

= 2( 700 + 500)

= 2 × 1200

= 2400m

.°. Length of the wire = 2.4 km or 2400m.

• Length of the rectangular box = 40 cm

Breadth of the rectangular box = 10 cm

Perimeter of rectangular box = 2 ( l + b )

= 2 ( 40 + 10 )

= 2 × 50

= 100 cm.

.°. Length of tape = 100 cm.

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Answer 2

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★ Question ★

A table top measures 2 m 25 cm by 1 m 50 cm. What is perimeter of the table. Give anser in both units one by one.

★ Solution ★

Perimeter of the table-top

$\bf= 2× (Length + Breadth)$

$\bf= 2 × (2 m 25 cm + 1 m 50 cm)$

$\bf= 2 × (2.25 m + 1.50 m)$

$\bf= 2 × (3.75 m)$

$\bf= 7.5m$

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★ Question ★

A rectangular piece of land measure 0.7 km by 0.5 km Each side is to be fenced with r rows of wires. What is length of wire needed?

★ Solution ★

Total perimeter =2(l+b)

$\bf=2(0.7+0.5)$

$\bf=2×1.2=2.4 km$

Since 4 rows is fenced at each side,

Total length of the wire needed

$\bf=4×2.4=9.6 km$

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★ Question ★

The lid of rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of he tape required?

★ Solution ★

The length of the tape would be equivalent to the perimeter.

$\bf=2×(L+B)$

$\bf=2(40+10)$

$\bf=2×(50)$

$\bf=100cm$

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★ Question ★

Show that perimeter of rectangle is 2(l+b) units.

★ Solution ★

Considered a rectangle ABCD in which AB and DC = L and AD and BC = B

To prove : P of rectangle = 2( L + B )

Proof : In rectangle ABCD we know that the sum of all sides is equal to its perimeter

Perimeter of given figure = L + B + L + B

perimeter of rectangle = 2L + 2B

perimeter of rectangle = 2 ( L + B )

( Hence prove )

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★ Hope you understand this concept mate ★