Question

Challenge Problems
By using the following clues, find who am I?
i) Each of my numerator and denominator is a single digit number.
ii) The sum of my numerator and denominator is a multiple of 3.
iii) The product of my numerator and denominator is a multiple of 4.​

Answer 1

Step-by-step explanation:

NNnJzjJjJ1u818289394994939e9

Answer 2

$\frac{1}{8}$ and $\frac{2}{4}$  these two fractions are the answer.

Step-by-step explanation:

Let the two numbers are = x (numerator) and y (denominator)

x + y = multiples of 3 ( 3, 6, 9, 12, 15, 18)

(x)(y) = multiples of 4 ( 4, 8, 12, 16)

If x = 1  and y = 8

$\frac{1}{8}$ = (1+8) = 9  that is multiple of 3

and (1×8) = 8 that is multiple of 4

other fraction would be :

$\frac{2}{4}$ = (2+4) = 6 that is multiple of 3

and (2×4) = 8 that is multiple of 4

$\frac{1}{8}$ and $\frac{2}{4}$  these two fractions are the answer.

Learn more challenge problems :

https://brainly.in/question/8552512