challenge solve it
Q8&9
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Q8→ here,
a=2
b=-3k
c=4
d=-5
so,
sum of zeroes=-b/a
6=-(-3k/2)
6=3k/2
6×2/3=k
k=4
-------------------------------------------------------
Q9→ let one zero be x
other zero=1/x
so,
multiply of zero=x×(1/x)=1
here,
a=5
b=13
c=k
so,
multiply of zero=c/a
1=k/5
k=1×5
k=5
a=2
b=-3k
c=4
d=-5
so,
sum of zeroes=-b/a
6=-(-3k/2)
6=3k/2
6×2/3=k
k=4
-------------------------------------------------------
Q9→ let one zero be x
other zero=1/x
so,
multiply of zero=x×(1/x)=1
here,
a=5
b=13
c=k
so,
multiply of zero=c/a
1=k/5
k=1×5
k=5
Answered by
2
Follow this picture......it's simple zeroes application...on the first question answer is 4 and second answer is 5
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