Question

CHALLENGE SOLVE THIS CORRECT IF YOU CAN...​

Answer 1

Answer:

Heya ! there

Your Answer is 1189

Reason , 1 + 2 = 123

Sum of 1 + 2 = 3 it's on one unit , 1 × 2 = 2 tens place , Hundred digit = 1

Similarly 2 + 3 = 165 ,

Sum of 2 + 3 = 5 it's on one place , 2 × 3 = 6 on tens place and Hundred unit = 1

3 + 4 = 1127 , on one place , 3 + 4 = 7

ten's place 3 × 4 = 12 and Hundred as same

Similarly

3 + 6 = on one's place 6 + 3 = 9

and ten's place = 6×3 = 18 and Hundred as same = 1

So number is 1189

Answer 2

$\huge\underline\mathfrak\pink{Answer-}$

3 + 6 = 1189

$\huge\underline\mathfrak\pink{Explanation-}$

If we look at the question, we see that 1 is common among all the sequences initially.

1 + 2 = $\boxed{\blue{1}}$23

2 + 3 = $\boxed{\blue{1}}$65

3 + 4 = $\boxed{\blue{1}}$127

7 + 8 = $\boxed{\blue{1}}$5615

So, Ist digit should be 1.

So, Ist digit should be 1.3 + 6 = 1 _ _ _

Secondly, we see that, when we multiply the given numbers, we get required number which is on second position. Like :

1 + 2 = 1$\boxed{\blue{2}}$3 [ Here 1 × 2 = 2 ]

2 + 3 = 1$\boxed{\blue{6}}$5 [ Here 2 × 3 = 6 ]

3 + 4 = 1$\boxed{\blue{12}}$7 [ Here 3 × 4 = 12 ]

7 + 8 = 1$\boxed{\blue{56}}$15 [ Here 7 × 8 = 56 ]

So, 2nd and 3rd digit should be 18.

So, 2nd and 3rd digit should be 18.3 + 6 = 1 1 8 _ [ Here 3 × 6 = 18 ]

Now, at last we see that, when we add the given numbers we get the required value. Like :

1 + 2 = 12$\boxed{\blue{3}}$ [ Here 1 + 2 = 3 ]

2 + 3 = 16$\boxed{\blue{5}}$ [ Here 2 + 3 = 5 ]

3 + 4 = 112$\boxed{\blue{7}}$ [ Here 3 + 4 = 7 ]

7 + 8 = 156$\boxed{\blue{15}}$ [ Here 7 + 8 = 15 ]

So, 4th digit should be 9.

So, 4th digit should be 9.3 + 6 = 1 1 8 9 [ Here 3 + 6 = 9 ]

________________

Therefore, 3 + 6 = 1189 [ Required answer ]

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