Math, asked by Anonymous, 3 months ago

♡CHALLENGE :

❥The internal bisectors of angles B and C of a triangle ABC meet at O. Then, ∠BOC is equal to :

(a) \: 90°  + A


(b) \: 2A


(c) \: 90° +  \frac{1}{2}A


(d) \: 180° - A

Answers

Answered by amanraj56
1

Answer:

its a theorem BOC = 90+ A/2

if it bisects ecternally then BOC= 90-A/2

#666

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