Question

challenge to brainly solvethis​

Answer 1

In ∆MOC:-

angle MOC = 80°⠀ ...(AOB and MOC are vertically opposite angles)

angle MCO = 45°⠀...(angleMCB=90° and diagonal AC bisects this angle)

angle $x$ = angle MCO + angle MOC ...( $x$ is exterior angle of ∆MOC)

angle $x$ = 80° + 45°

angle $x$ = 125°

Your Answer = angle $x$=125°

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Answer 2

Answer

Give angle AOB=80

Therefor angleCOM=80°(vertically opposite angles )

As ABCD is a square ..

AngleMCO=45°

angle OMC=180-(80+45)

=55

angle DMO +angleCMO=180°

angle DMO=X=180-55=125.

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