Question

challenge to brainly solvethis
giving u 50 points solve this​

Answer 1

Answer:

$x =55° \\ y =35° \\ z = 90°$

Step-by-step explanation:

Sol.5)As AB||CD and EF is transversal

$\angle \: CQF= \angle \: APQ \: (corresponding \: angle) \\ \\ 65° = 30°+ y \\ \\ y = 65° - 30° \\ \\ y = 35°$

Now,

$\angle \: CQF+ \angle \: CQR+ \angle \: RQF = 180° \: \: \: (EQ \: is \: straight \: line)$

$65° + 25° + z = 180° \\ \\ z = 180° - 90° \\ \\ z = 90°$

Now

$x + y + z = 180°(angle \: sum \: property \: of \: triangle) \\ \\ x + 35° + 90°= 180°\\ \\ x = 180° - 125° \\ \\ x = 55°$

Solution 6:

$\angle \:D = \angle \: C=90°\: \: \: (angles\: of \: square\: ) \\\angle \:EDC = \angle \: ECD=60°\: \: \: (angles\: of \: equilateral \: triangle) \\\angle \:D+\angle \:EDC = \angle \: C+\angle \: ECD=150°\\\angle\:ADE= \angle \: ECB=150°$

AD=BC(sides of square)

DE=CE(given,∆DEC equilateral triangle)

$\angle\:ADE= \angle \: ECB(proved\:above)$

by SAS CRITERION of CONGRUENCY

$\triangle \:ADE\cong \triangle BCE$

HENCE PROVED.

Hope it helps you.

Answer 2

Answer:

Step-by-step explanation:

Sol.5)As AB||CD and EF is transversal

Now,

Now

Solution 6:

AD=BC(sides of square)

DE=CE(given,∆DEC equilateral triangle)

by SAS CRITERION of CONGRUENCY

HENCE PROVED.

Read more on Brainly.in - https://brainly.in/question/15859115#readmore