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x³ + 1/x³ if x+ 1/x = 3
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Hii !!
X + 1/x = 3
Cubing both sides,we get
( X + 1/X)³ = (3)³
X³ + 1/X³ + 3 X × 1/X ( X + 1/X ) [ ( a + b )³ = a³ + b³ + 3ab ( a + b) ]
X³ + 1/X³ + 3 ( 3 ) = 27
X³ + 1/x³ + 9 = 27
X³ + 1/x³ = 27 - 9
X³ + 1/X³ = 18
X + 1/x = 3
Cubing both sides,we get
( X + 1/X)³ = (3)³
X³ + 1/X³ + 3 X × 1/X ( X + 1/X ) [ ( a + b )³ = a³ + b³ + 3ab ( a + b) ]
X³ + 1/X³ + 3 ( 3 ) = 27
X³ + 1/x³ + 9 = 27
X³ + 1/x³ = 27 - 9
X³ + 1/X³ = 18
thank you
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