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Find the remainder, when x4 + 4x3 - 5x2 - 6x + 7 is divided by x-1
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The remainder left is 1.
The calculation is as follows:
x-1 )x^4+4x^3-5x^2-6x+7( x^3-5x^2-6
x^4-x^3
- +
0- 5x^3-5x^2
- 5x^3-5x^2
+. +.
0 + 0 -6x+7
-6x+6
+. -.
0 +1
Hence, the answer is 1.
Hope I was able to help!
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