Math, asked by ridak8779, 5 months ago

CHALLENGERS
Find the remainder, when x4 + 4x3 - 5x2 - 6x + 7 is divided by x-1

Answers

Answered by ruru13

5

The remainder left is 1.

The calculation is as follows:

x-1 )x^4+4x^3-5x^2-6x+7( x^3-5x^2-6

x^4-x^3

- +

0- 5x^3-5x^2

- 5x^3-5x^2

+. +.

0 + 0 -6x+7

-6x+6

+. -.

0 +1

Hence, the answer is 1.

Hope I was able to help!

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