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In the following figure, AOB is a straight angle. OQ
is the bisector of AOC and OP is the bisector of BOC.
If | AOC = 60°, then find i) BOC ii) POQ.
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Given : AOB is a straight line
OQ is the bisector of AOC
OP is the bisector of BOC
∠AOC = 60°
To Find : ∠BOC , ∠POQ
Solution:
AOB is a straight line
∠AOC and ∠BOC form a linear pair
=> ∠AOC + ∠BOC = 180°
=> 60° + ∠BOC = 180°
=> ∠BOC = 120°
∠POQ = ∠POC + ∠QOC
∠POC = (1/2) ∠BOC
=> ∠POC = (1/2) 120°
=> ∠POC = 60°
∠QOC = (1/2) ∠AOC
=> ∠QOC = (1/2) 60°
=> ∠QOC = 30°
∠POQ = ∠POC + ∠QOC
=> ∠POQ = 60° + 30°
=> ∠POQ = 90°
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