Question

( Challenging Questions
1. There are 5 red and 3 green pens in a bag. There
are 2 red and 6 green pens in another bag. A pen
is picked up at random from one bag. Using the
following instructions, find the probability that
the pen picked up :
(a) from one bag is red.
(b) from another bag is red.
(c) from either of the bags is red.​

Answer 1

Step-by-step explanation:

a) probability

5/8

b) probability

2/8

1/4

c) probability

7/8

hope it is correct

pls mark me the brainliest......

Answer 2

a)5/8

b)1/4

c) 0

Step-by-step explanation:

sample space for one bag ={1 red,2red,3red,4red,5red,1green,2green,3green}

therefore Sample points n(S1)= 8 balls

Sample space for another bag={ 1red,2red,6 green}

now let A event be pen picked by one bag is red

Event A={ 5 red balls}

n(A)= 5

p(A) = n(A)/n(S1)

5/ 8

therefore in one bag is 5/8 probability.

Now let Event B={ 2 red }

n(B)= 2

p(B)= n(B)/ n(S2)

=2/8

= 1/4

Event C ={ 0}

p(C)= 0