chance of having 53 Sundays in a leap year if random selecte
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Answer:
2/7
Step-by-step explanation:
The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.
So there are 7 possibilities out of which 2 have a Sunday. So the probability of. 53 Sundays in a
leap year is 2/7.
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