CHANCE TO BE BRAINLY STAR BY ANSWERING THIS QUESTION ----------
P and Q start walking around a circular track from same point. P walks in CW direction and Q in ACW. P completes 4 rounds in an hour. Q completes 5 rounds in an hour. How many times P and Q meet each other if both of them walk for 40 min ?
Sneha3123:
just tell be y a user will become bs after answering this question only?
YESS OF COURSE do fast dont miss this chance
oooo
really
i think you don't know
but i m already a bs
Mr. Vikas dont try to fool her she is a brainly star and she knows how to become a brainly star..... -_-
He fooled
he just need answer fast , so he used a trick
Hahahah
Answers
Answered by
4
Heya user !!!
Here's the answer you are looking for
First of all don't spread this rumour. No one is going to be a brainly star just by answering a single question. -_-
And please see the attached file for your answer
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
First of all don't spread this rumour. No one is going to be a brainly star just by answering a single question. -_-
And please see the attached file for your answer
★★ HOPE THAT HELPS ☺️ ★★
Attachments:
nice handwriting
Thanks
you are welcome
Gr8 answer
I KNEW THE ANSWER
Nice!!!
Answered by
4
hello users.......
given that
P and Q start walking around a circular track from same point. P walks in CW direction and Q in ACW
and also
P completes 4 rounds in an hour
& Q completes 5 rounds in an hour
=> speed of P is = 4 rounds per hour
&
speed of Q is = 5 rounds per hour
solution:-
to get answer
let suppose that Q is at rest and P is moving
then the relative speed of P = 4+5 = 9 rounds per hour
in 1 hour P will complete = 9 rounds
in 1 minute P will complete = 9/60 rounds
in 40 minutes P will complete = 9×40/60
= 6 rounds
hence
In 40 minutes P and Q meet each other = 6 times
⭐✡ hope it helps ⭐✡
given that
P and Q start walking around a circular track from same point. P walks in CW direction and Q in ACW
and also
P completes 4 rounds in an hour
& Q completes 5 rounds in an hour
=> speed of P is = 4 rounds per hour
&
speed of Q is = 5 rounds per hour
solution:-
to get answer
let suppose that Q is at rest and P is moving
then the relative speed of P = 4+5 = 9 rounds per hour
in 1 hour P will complete = 9 rounds
in 1 minute P will complete = 9/60 rounds
in 40 minutes P will complete = 9×40/60
= 6 rounds
hence
In 40 minutes P and Q meet each other = 6 times
⭐✡ hope it helps ⭐✡
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