Question

chandadavi borrowed some money for 2 years in the compound interest at the rate of 8% per annum. let us calculate if the compound interest is ₹ 2496, then how much money she had lended.​

Answer 1

A = P (1 + r/n) (nt)
use this formula u will reach your answer

Answer 2

$principal + compound \: intrest = \:P ( 1 + \frac{8}{100})^2$

$p+2496 = \:p ( 1 + \frac{8}{100} )^2$

$p+2496 = \:p ( \frac{108}{100} )^2$

$p+2496 = \:p× \frac{108}{100} × \frac{108}{100}$

$p + 2496 = \:p × \frac{54}{50} × \frac{54}{50}$

$(p + 2496)×2500 = \:p × 54 ×54$

$2500p + 6240000 = \:2916p$

$-416p = \: -6240000$

$p = \frac{ -6240000}{ -416}$

$p = 15000$

so she lended ₹15000