change 1.5270(bar on 270) to p/q form by long method.
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it can be written as
x = 1.5270270270270.................. (1)
multiplying by 10
10x=15.270270270..................... (2)
multiply (1) by 10000
10000x=15270.270270270................. (3)
subtracting (2) from (3)
10000x-10x=15270.270270....-15.270270270..
9990x = 15255
x = 15255/9990
this is the required p/q forn
x = 1.5270270270270.................. (1)
multiplying by 10
10x=15.270270270..................... (2)
multiply (1) by 10000
10000x=15270.270270270................. (3)
subtracting (2) from (3)
10000x-10x=15270.270270....-15.270270270..
9990x = 15255
x = 15255/9990
this is the required p/q forn
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