Question

Change (3k+2) into [3(k+1)-1]..explain the steps please..

Answer 1

Answer:

(3k + 2) = [ 3 ( k + 1) -1]

RHS = [ 3 ( k + 1) -1]

= 3k + 3 - 1

3k + 2 = LHS

THEREFORE , LHS = RH

(3k + 2) = [ 3 ( k + 1) -1]