Question

Change each of the given temperature to the Celsius and Kelvin scales : 68^@ F, 5^@ F and 176 ^@ F.

Answer 1

do the remaining using same equation

thank you

Answer 2

$\Large{\underline{\underline{\bf{Solution :}}}}$

We know that,

$\large{\implies{\boxed{\boxed{\sf{\frac{C}{5} = \frac{K - 273}{5} = \frac{F - 32}{9}}}}}}.....(1)$

Where,

C = Celsius

F = Fahrenheit

K = Kelvin

$\rule{150}{2}$

F = 68°

Now, A.T.Q

$\sf{→\frac{C}{5} = \frac{68 - 32}{9}} \\ \\ \sf{→C = \frac{\cancel{36} \times 5}{\cancel{9}}} \\ \\ \sf{→C = 4 \times 5} \\ \\ \sf{→C = 20} \\ \\ \sf{So, \: 68^{\circ}F = 20^{\circ}C....(2)}$

$\rule{150}{2}$

Now,

$\sf{→\frac{K - 273}{5} = \frac{68 - 32}{9}} \\ \\ \sf{→K - 273 = \frac{\cancel{36} \times 5}{\cancel{9}}} \\ \\ \sf{→K - 273 = 4 \times 5} \\ \\ \sf{K - 273 = 20} \\ \\ \sf{→K = 20 + 273} \\ \\ \sf{K = 293} \\ \\ \sf{So, 20^{\circ}C = 293^{\circ}K ......(3)}$

★ From equation (2) and (3)

‡ 68°F = 20°C = 293°K

$\rule{200}{2}$

F = 5°

$\sf{→\frac{C}{5} = \frac{5 - 32}{9}} \\ \\ \sf{→C = \frac{\cancel{-27} \times 5}{\cancel{9}}} \\ \\ \sf{→C = -3 \times 5} \\ \\ \sf{→C = -15} \\ \\ \sf{So, \: 5^{\circ}F = -15^{\circ}C....(4)}$

$\rule{150}{2}$

Now,

$\sf{→\frac{K - 273}{5} = \frac{5 - 32}{9}} \\ \\ \sf{→K - 273 = \frac{\cancel{-27} \times 5}{\cancel{9}}} \\ \\ \sf{→K - 273 = -3 \times 5} \\ \\ \sf{K - 273 = 20} \\ \\ \sf{→K = -15 + 273} \\ \\ \sf{K = -258} \\ \\ \sf{So, -15^{\circ}C = -258^{\circ}K ......(5)}$

★ From equation (4) and (5)

5°F = -15°C = -258°K

$\rule{200}{2}$

F = 176°

Now, A.T.Q

$\sf{→\frac{C}{5} = \frac{176 - 32}{9}} \\ \\ \sf{→C = \frac{\cancel{144} \times 5}{\cancel{9}}} \\ \\ \sf{→C = 16 \times 5} \\ \\ \sf{→C = 80} \\ \\ \sf{So, \: 176^{\circ}F = 80^{\circ}C....(6)}$

$\rule{150}{2}$

Now,

$\sf{→\frac{K - 273}{5} = \frac{176 - 32}{9}} \\ \\ \sf{→K - 273 = \frac{\cancel{144} \times 5}{\cancel{9}}} \\ \\ \sf{→K - 273 = 16 \times 5} \\ \\ \sf{K - 273 = 20} \\ \\ \sf{→K = 80 + 273} \\ \\ \sf{K = 353} \\ \\ \sf{So, 176^{\circ}C = 353^{\circ}K ......(7)}$

★ From equation (6) and (7)

176°F = 80°C = 353°K